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Let us see how to print the last field alone from a file which contains several fields.
Let's say that the input is the below file.
Now we need to Print the last field. i.e.
The required Output would be:
----------------------------------
7
4
8
8
We can do this by three ways.
1) The normal awk way of doing it:
$ awk 'BEGIN {FS=":"} {print $NF}' priority.txt
2) Using sed:
$ sed -n 's/.*://;p' priority.txt
3) Using grep:
$ grep -o '[^:]*$' priority.txt
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